Homework #15 Solutions
15.
Ho:
H1:
df1 = 21 – 1 = 20 df2 = 18 – 1 = 17 Ho is rejected if F > 3.16
Reject Ho. There is more variation in selling price of ocean front
homes.
16.
Ho:
H1:
df1 = 16 – 1 = 15 df2 = 16 – 1 = 15 Ho is rejected if F > 2.40
Reject Ho. There is more variation in processing time of the new
machine.
17. Sharkey: n = 7 sd = 14.79
White: n = 8 sd = 22.95
Ho:
H1:
dfs = 7 – 1 = 6 dfw = 8 – 1 = 7 Ho is rejected if F > 8.26
Cannot
reject Ho. There is no difference in the variation of the weekly sales.
18. a. Ho: m1 = m2 = m3 H1: Treatment means are not all equal
b. a = 0.05 Reject if F > 3.89
c. Source SS df MS F
Treatment 40 2 20 4
Error 60 12 5
Total 100 14
d. Reject Ho. The treatment means are not all equal.
19. a. Ho: m1 = m2 = m3 = m4 H1: Treatment means are not all equal
b. a = 0.05 Reject if F > 3.10
c. Source SS df MS F
Treatment 50 3 16.67 1.67
Error 200 20 10
Total 250 23
d. Do not reject Ho.
20. Source SS df MS F
Treatment 320 2 160 8.00
Error 180 9 20
Total 500 11
a. 3
b. 12
c. 4.26
d. Ho: m1 = m2 = m3 H1: Not all means are equal
e. Ho is rejected. The treatment means differ.
21. Ho: m1 = m2 = m3 H1: Not all means are equal
Ho is rejected if F > 3.89
Source SS df MS F
Treatment 63.33 2 31.667 13.38
Error 28.40 12 2.367
Total 91.73 14
Ho is rejected. There is a difference in the treatment means.
22. Ho: m1 = m2 = m3 H1: Not all means are equal
Ho is rejected if F > 3.89
Source SS df MS F
Treatment 26.13 2 13.065 13.52
Error 11.60 12 0.967
Total 37.73 14
Ho is rejected since 13.52 > 3.89. There is a difference in the mean weight loss among the three diets.
23. Ho: m1 = m2 = m3 = m4 H1: Not all means are equal
Ho is rejected if F > 3.10
Source SS df MS F
Factor 87.79 3 29.26 9.12
Error 64.17 20 3.21
Total 151.96 23
Since computed F of 9.12 > 3.10, the null hypothesis of no difference is rejected at the 0.05 level.
24. a. Ho: m1 = m2 = m3 H1: Not all means are equal
Ho is rejected if F > 3.68
Source SS df MS F
Treatment 116.3 2 58.2 5.09
Error 171.5 15 11.4
Total 287.8 17
Reject Ho. There is a difference in the mean scores
b.
Yes, because both endpoints are positive.
The mean perfectionism scores for those from a rural background differs from those with an urban background.
You may also download an EXCEL spreadsheet called anova4u.xls. It contains my solutions to various problems from the text and the EXCEL workbook related to the F-test and ANOVA.